50y^2-10y=0

Solution for 50y^2-10y=0 equation:

50y^2-10y=0

a = 50; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·50·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*50}=\frac{0}{100}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*50}=\frac{20}{100}
=1/5
$